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How many different natural numbers less than 200 are exactly divisible by either 6 9 or by both?
To find the natural numbers less than 200 that are divisible by 6, 9, or both, we can use the principle of inclusion-exclusion. First, the count of numbers divisible by 6 is ( \left\lfloor \frac{199}{6} \right\rfloor = 33 ), and for 9, it is ( \left\lfloor \frac{199}{9} \right\rfloor = 22 ). The count of numbers divisible by both 6 and 9 (i.e., 18) is ( \left\lfloor \frac{199}{18} \right\rfloor = 11 ). Applying inclusion-exclusion, we get ( 33 + 22 - 11 = 44 ). Thus, there are 44 different natural numbers less than 200 that are exactly divisible by either 6, 9, or both.
What is 199 decreased by 9 percent?
199 - 9% = 199 x (1 - (9/100)) = 199 x 0.91 = 181.09.
Is ten to the power of 199 a prime number?
No, it would be divisible by ten.
Is 199 divisible by 11?
Not evenly. The answer would be 18 remainder 1.
What numbers between 100 and 199 are divisible by 8?
There are 12 numbers between 100 and 199 that are divisible by eight: 104, 112, 120, 128, 136, 144, 152, 160, 168, 176, 184 and 192.
What numbers is not divisible by 9 81 162 199 1125?
81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
Which of the numbers is divisble by 3 199 209 390 or 499?
Here's a mathematical trick. Any number wholly divisible by 3 has the sum of its digits equal to 3 or a multiple of 3. 199 : 1 + 9 + 9 = 19....NOT divisible by 3 209 : 2 + 0 + 9 = 11....NOT divisible by 3 390 : 3 + 9 + 0 = 12....YES, this is divisible by 3 499 : 4 + 9 + 9 = 22....NOT divisible by 3 Note : 390 ÷ 3 = 130
How many different natural numbers less than 200 are exactly divisible by either 6 9 or by both?
To find the natural numbers less than 200 that are divisible by 6, 9, or both, we can use the principle of inclusion-exclusion. First, the count of numbers divisible by 6 is ( \left\lfloor \frac{199}{6} \right\rfloor = 33 ), and for 9, it is ( \left\lfloor \frac{199}{9} \right\rfloor = 22 ). The count of numbers divisible by both 6 and 9 (i.e., 18) is ( \left\lfloor \frac{199}{18} \right\rfloor = 11 ). Applying inclusion-exclusion, we get ( 33 + 22 - 11 = 44 ). Thus, there are 44 different natural numbers less than 200 that are exactly divisible by either 6, 9, or both.
What is 597 divisible by?
1, 3, 199, 597.
What is 199 decreased by 9 percent?
199 - 9% = 199 x (1 - (9/100)) = 199 x 0.91 = 181.09.
What is the number of the integers between 101 and 199 which are exactly divisible by 5 or 7?
19 divisible by 5, 14 divisible by 7. Of these, 3 divisible by both.
Is ten to the power of 199 a prime number?
No, it would be divisible by ten.
Is 199 divisible by 11?
Not evenly. The answer would be 18 remainder 1.
Is 597 divisible by 3?
Yes because 597/3 = 199
Is 119 divisible by 3?
no, an easy way to find dat is do this: 119 --> 1+1+9=11, then 1+1=2, if thats 3, 6, or 9, then its divisible. ex: is 12,345 divisible by 3, lets find out! 1+2+3+4+5=15, then 1+5=6, there you go, 12,345 is divisible by 3 (119 isn't, 199 divided by 3 is 39.666)
What numbers between 100 and 199 are divisible by 8?
There are 12 numbers between 100 and 199 that are divisible by eight: 104, 112, 120, 128, 136, 144, 152, 160, 168, 176, 184 and 192.
Is 1110 divisible by 9?
NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)
