(x + 12)(x - 3)
49x2 - 84x + 36 = (7x - 6)(7x - 6) or (7x - 6)2
x^(2) - 12x + 36 Look for two factors of '36', that add/subtract to '12'. ;- 1,36 ; 2,18; 4,9; 6,6. The last pair 6 & 6 add to ;12; Hence (x 6 )(x 6) Which signs???? Since '36' is positive(+), then both the signs are the same. They can be both negative , or both positive. Since the sign in '12x' is hegative then they are both negative. Hence (x - 6)(x - 6) Done!!!!!
x(x2 + 36)
(x - 6)(x^2 + 6x + 36)
(x + 4)(x + 9)
2x^(2) + 72 Factors to 2( x^(2) + 36) s(x^(2) + 6^(2)) Does NOT factor. NB Remember . two squared terms with a positive(+) between them does NOT factor!!!! However, two squared terms with a negative(-) between DOES factor . e.g. x^(2) + 6^(2) Does NOT factor x^(2) - 6^(2) factors to ( x - 6)( x + 6 ) Note the different signs. Similarly 8^(2) + 6^(2) does NOT factor 8^(2) - 6^(2) factors to (8 - 6)(8 + 6) Or using the ~Pythagorean Equation. h^(2) = a^(2) + b^(2) Does NOT factors However, a^(2) = h^(2) - b^(2) factors to a^(2) = (h - b)(h + b) .
(6x - 1)(6x - 1)
49x2 - 84x + 36 = (7x - 6)(7x - 6) or (7x - 6)2
9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)
x2-5x-36 = (x-9)(x+4) when factored
4(y - 3)(y + 3)
(5x - 6)(5x + 6)
(x + 6)(x - 6)
x^(2) - 13x + 36 Factors to ( x - 9)(x - 4)
x2 + 36 cannot be factored. You can only factor the difference of two squares, not the sum.
(5w-6)2
0 = 2m^2 - 2m + 36 0 = 2(m^2 - m + 18) 0 = m^2 - m + 18