To find the number of 3-digit combinations that can be made from the digits 1, 2, 3, 4, and 5, we consider that each digit can be used only once in each combination. The number of combinations is calculated using the formula for combinations: ( \binom{n}{r} ), where ( n ) is the total number of items to choose from, and ( r ) is the number of items to choose. Here, ( n = 5 ) and ( r = 3 ), so the number of combinations is ( \binom{5}{3} = 10 ).
6 of them.
There are 15180 combinations.
To find the number of three-digit combinations, we consider the digits from 000 to 999. Each digit can range from 0 to 9, giving us 10 options for each of the three digits. Therefore, the total number of three-digit combinations is (10 \times 10 \times 10 = 1,000).
There are 5,461,512 such combinations.
There are a total of 1,000 three-digit combinations from 000 to 999. This includes all combinations where the digits can range from 0 to 9, allowing for repetitions. Each of the three digit positions can have 10 possible values (0-9), leading to (10 \times 10 \times 10 = 1,000) combinations.
Just 1.
There are 126 different 5 digit combinations. Note that the combination 12345 is the same as the combination 45312.
There are 9C3 = 84 combinations.
120 5-digit numbers can be made with the numbers 12345.
There are: 12345C3 = 3.134847985*1011
6 of them.
Only one.
How many four digit combinations can be made from the number nine? Example, 1+1+2+5=9.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
125
"There are 10,000 different combinations"-Hey nick! love dave and jalp
There are 15180 combinations.