10.
There are 120 permutations and 5 combinations.
To find the number of 3-digit combinations that can be made from the digits 1, 2, 3, 4, and 5, we consider that each digit can be used only once in each combination. The number of combinations is calculated using the formula for combinations: ( \binom{n}{r} ), where ( n ) is the total number of items to choose from, and ( r ) is the number of items to choose. Here, ( n = 5 ) and ( r = 3 ), so the number of combinations is ( \binom{5}{3} = 10 ).
60 choices The way you get this answer is 5 times 4 times 3 if there are no repeats. That is mathematically speaking the number of Permutations of 3 from 5. The number of mathematical Combinations (where order doesn't matter, ie groupings) of 3 from 5 is 10.
654321-100000= 554321 combinations
There are 5,461,512 such combinations.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are 120 permutations and 5 combinations.
To find the number of 3-digit combinations that can be made from the digits 1, 2, 3, 4, and 5, we consider that each digit can be used only once in each combination. The number of combinations is calculated using the formula for combinations: ( \binom{n}{r} ), where ( n ) is the total number of items to choose from, and ( r ) is the number of items to choose. Here, ( n = 5 ) and ( r = 3 ), so the number of combinations is ( \binom{5}{3} = 10 ).
60 choices The way you get this answer is 5 times 4 times 3 if there are no repeats. That is mathematically speaking the number of Permutations of 3 from 5. The number of mathematical Combinations (where order doesn't matter, ie groupings) of 3 from 5 is 10.
There are 7C4 = 7!/(4!*3!) = 7*6*5/(3*2*1) = 35 combinations.
There is 345, 354, 435, 453, 543, 534.
654321-100000= 554321 combinations
Assuming a number can appear only once, there are 47C5 = 47*46*45*44*43/(5*4*3*2*1) = 1,533,939 combinations.
The rearrangement of 5 figure numbers will be 5x4x3x2x1 which is 120 combinations, when you don't repeat a number.
just intrested in the number combinations * * * * * Number of combinations = 56C6 = 56*55*54*53*52*51/(6*5*4*3*2*1) = 32,468,436
There are 11,238,513 of them.
There are 5,461,512 such combinations.